Gas Laws

A bulb is filled with 20g of CO2 gas at 296Kand 1atm.The bulb is heated to 336K,and the stopcock is opened.How much CO2 escapes,if the external pressure is 1atm when the stopcock is opened and the bulb is kept at 336K?When the pressure inside the bulb reaches 1atm,the stopcock is closed again.

12 Answers

24
eureka123 ·

is last sentence complete?????
""When the pressure inside the bulb reaches 1atm,the stopcock is closed again.""

1
JOHNCENA IS BACK ·

i think no CO2 should escape.

6
nix_13 12 ·

yes the last sentence is complete

6
nix_13 12 ·

hey cena.....ur ans is wrong coz 2.4 g of CO2 escapes

1
JOHNCENA IS BACK ·

oops!!!!!!!!!!!did not read the ques properly that temp. is changed by heating.

1
JOHNCENA IS BACK ·

volume of bulb=20*R*296/44
so,final no. of moles in bulb=20*296/(336*44)
so,final weight of CO2 in bulb=17.619 g

so amount of CO2 escaped=2.38=2.4g

6
nix_13 12 ·

how did u get volume of bulb=20*R*296/44 and final no. of moles in bulb=20*296/(336*44)???

1
JOHNCENA IS BACK ·

use ideal gas equation PV=nRT at initial temp.

and then at final temp.

11
virang1 Jhaveri ·

v1/t1=v2/t2

V/296 = V2/336
V2 =336V/296
V2 = 1.135V
Since the bulb holds only 1V
The escaping volume is 0.135V
1.135V is 20g
0.135V is
20*0.135/1.135
= 2.378g
= 2.38g

11
virang1 Jhaveri ·

Nishant Bhaiyya pls check it out

62
Lokesh Verma ·

yup good work john and virang..

6
nix_13 12 ·

thx for the answer guys ........but....how did u get the idea that u should use charles law???is there any other method???Or instead of telling me the answers plz tell me how to thhink over the problems n help me improve my problem solving skills......plz help!!!!!

Your Answer

Close [X]