gas laws

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1. One litre water in a bucket is placed in a closed dry air room having dimensions 4*2*1.5 m^3 at 300K. If the vapour pressure of water at 300K is 27.0mm and density of water at 300K is 0.990 g cm^(-3), calculate the amount of water left in liquid state.

#Chemistry #Physical Chemistry

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1357

Manish Shankar ·2012-08-12 04:26:48

pressure of water vapour=27 mm=27/760 atm

volume of water vapour=4*2*1.5=12 m^3=12000 L

moles of water vapour=PV/RT=27*12000/(760*0.082*300)=17.3

weight of water vapour=17.3*18=311.4 g

initial weight of water = 990 g

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