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a closed container of volume 0.02m3 contains mixture of neon and argon gases at a temperature 27°C.pressure 1*10^5.the total mass is 28g.if gram molecular weight of neon and argon is 20 and 40 find masses of indiviual gases.
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3 Answers
qwerty
·2010-11-22 03:12:15
n1 = moles of neon
n2 = moles of argon
n2 + n1 = PV/RT = 105 x 0.02 / 8.3 x 300
20n1+40n2 = 28
solve these 2 eqns , find moles of each , and then mass will be no of moles x molar mass