graph

plot a curve depicting the temperature dependence of the rate R of a simple one step reaction.

24 Answers

1
JOHNCENA IS BACK ·

@ RAM,
BHAI,GRAPH B/W RATE(R) AND TEMP.(T).FROM WHERE THIS k CAME IN?????????

62
Lokesh Verma ·

Ramkumar and john..

I made a mistake...

Ramkumar's graph was correct...

See the thing is that the exponential power is -Ea/RT

as T-> 0 kelvin, -Ea/RT goes to - infinity

exp (-Ea/RT) goes to zero...

1
JOHNCENA IS BACK ·

yup,i know that but in answer the same graph starts from origin,plz explain

62
Lokesh Verma ·

For Ramkumar..

1
JOHNCENA IS BACK ·

graph!!!!!!!!!

1
~AjInKyA~ ·

plot a curve depicting the temperature dependence of the rate R of a simple one step reaction.
this is ur q 1
u mean 1 step
so 2nd order kyaaaaaa ?

1
~AjInKyA~ ·

come in chatbox !

1
JOHNCENA IS BACK ·

QUES.IS COMPLETE......BE CONVINCED

1
~AjInKyA~ ·

DUDE ! UR Q IS INCOMPLETE
TER R MANY RATE REACTIONS !
EXO OR ENDO ??
then 2 graphs possible !!

1
Pavithra Ramamoorthy ·

srry john.. pretended it as rate constant.......... very srry.......

wait let me post d correct one....

1
JOHNCENA IS BACK ·

EUREKA GRAPH IS CORRECT BUT IT JUST STARTS FROM ORIGIN.

24
eureka123 ·

john..........
whom are u sying that?to me or ram???????

my graph is rate v/s temperature

1
Pavithra Ramamoorthy ·

24
eureka123 ·

1
Pavithra Ramamoorthy ·

hey.. then wat does ur q mean???????

temp dependance means?????????? think of it..........

q is how does k vary with respect to time...........

1
JOHNCENA IS BACK ·

AGAIN k ON Y AXIS..........HUH.

1
Pavithra Ramamoorthy ·

srry fr editin after pinkin.. got a small mistake.. corected now

1
JOHNCENA IS BACK ·

EUREKA DO POST THE GRAPH.

24
eureka123 ·

A----->B+C
rate=k[A]m -----(1)
accc to arrhenius eqn
k=Ze-E/RT

put in eqn 1
=>Rate=Ze-E/RT[A]m
=>Rate=peT where p is constaant
made a change here

1
JOHNCENA IS BACK ·

HEY,I NEED GRAPH BETWEEN R(RATE) AND T(TEMP.) FOR A SIMPLE ONE STEP REACTION. CHECK UR GRAPH.....WHY TAKEN K(y) AND 1/T(X)

1
Pavithra Ramamoorthy ·

oh!!!!!!!!!!!

not linear?????????????? [7][7]

1
JOHNCENA IS BACK ·

HINT:acc. to answer(i am not able to solve) given graPH IS NOT A STRAIGHT LINE.IT IS A CURVE.

MAY BE THIS HELPS.

1
Pavithra Ramamoorthy ·

i mean it varies with 1/T with havin values in y axis as 0

1
Pavithra Ramamoorthy ·

THE GRAPH IS COINCIDED WITH X AXIS???????????

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