Helppppppp

IIT JEE 2015 Sample Questions › Physical Chemistry questions › Helppppppp

1.2g of a salt with their emperical formula K_xH_y(C₂O₄)_z was dissolved in 50mL of water and its 10mL part reqd 11mL of 0.1M HCl solution to reach equivalene point.IN a separate titration 15mL of stock solution reqd 20mL 0.2475M KOH to reach equivalence point.Determine emperical formula of salt

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2 Answers

1357

Manish Shankar ·2008-11-15 07:10:25

meq. of acid used=11*0.1

meq of salt used as base=11*0.1=((1.2/M)/50)*10*x (n-factor here is x)

meq of base used = 20*0.2475=((1.2/M)/50)*15*y

dividing one by other gives y/xâ‰ˆ3

also x+y=2z (neutral compound)

z=2x

x:y:z=1:3:2

so the salt is KH₃(C₂O₄)₂

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eureka123 ·2008-11-15 10:51:28

thanks......absolutely correct.......

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