24\Psi ^2=0=>\frac {1}{16(2\pi)}(\frac {1}{a_0})^3(2-\frac {r}{a_0})^2e^{-2r/a}=0
=> (2-\frac {r}{a_0})^2=0 =>2a_0=r
The Schrodinger wave equation for H-atom is
\large \Psi = \frac{1}{4\sqrt{2\Pi }}(a_0{})^-\frac{3}{2}{}\left(2 - \frac{}{r_0{}}a_0{} \right)e^-\frac{r_0{}}{a_0{}}{}
Where a0 is Bohr's Radius,if the radial node in 2s be at r0 then find r0 in terms of a0 ??
P.S - is schrodinger eqn there in the syllabus ??
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6 Answers
24Schrodinger eqn not in syllabus....but this question didnt demand any knowledge abt it....
the only info needed was probabality of finding e at node =0
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3actually eure it isnt necessary to find the probability density function isnt it or am i rong.
62No Schrodinger is not in syllabus.. But I think as eureka pointed out there was one question which used the phrase "schrodinger" but did not have any use of the equation...
all you need to know that probabiliyt is square of the wave function.. and zero at the nodes :)