An evacuated gass vessel weighs 50.0 g when empty, 148.0 g when filled with a liquid of density 0.98 gmL-1 and 50.5 g when filled with an ideal gas at 760 mm Hg at 300 K.
Determine the molecular weight of the gas.
106wt of liquid = 98 gm and density = 0.98 gm/L ==> vol. of container = 100 L
Now, wt of gas = 0.5 gm
==> PV = nRT
==> 1*100 = n*0.0821*300
==> n = 4 mol
==> 0.5/M = 4
==> M = 0.125 ??
21I took density as 0.98 gram / ml
oh !! graM KA SYMBOL TO g hota hai..... gm to hum apni pasand se likhte hain
11D =M/V
0.98 = 98/V
V= 100 *10-3
V = 0.1L
Weight of the Gas = 50.5 - 50
W = 0.5g
At 300k it occupies 0.1L
By Charles law
0.1*273/300
0.1*91/100 = V
Now the mass of Hydrogen for This volume
= 22.4 1
9.1/100 ?
m = 9.1/100*22.4
m = 0.4/100
VD = 0.5/0.4/100
Vd = 500/4 = 125
M.W = 250g
11But if it is l & not ml then the answer is
D =M/V
0.98 = 98/V
V= 100
V = 100l
Weight of the Gas = 50.5 - 50
W = 0.5g
At 300k it occupies 100L
By Charles law
0.1*273/300
100*91/100 = V
Now the mass of Hydrogen for This volume
= 22.4 1
91 ?
m = 9.1/100*22.4
m = 4
VD = 0.5/4
Vd = 0.125
M.W = 0.125g
Which is extremely small and therefore the answer in the before post is rite