IIT JEE past question Gasseous state

The compression factor (compressibilty factor) for aone mole of a van der waals gas at 0°C and 100 atm pressure is 0.5.
Assuming that the volume of a gas molecule is negligible, calculate the Van der Waals constant a

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1
Aditya ·

Compressibility factor Z=PV/RT

So, 0.5=100*V/0.082*273

V=0.112 L

As b is negligible, (P+a/V2)V=RT

Solving,

a=1.25 atmL2mol-2

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