rate is constant so ...
k(normal condition) = k(catalytic condition)
=> Ea / Ea(cat) = T/T(cat)
=> Ea / Ea - ΔE = T/T(cat)
=> Ea/Ea-20 = 5/4
=> 4Ea = 5Ea - 100
=>Ea=100kJ.
A hydrogenation reaction is carried out at 500K. If the same raction is carreid out in th epresence of a catalyst at the same rate the temperature required is 400K.
calculate the Activation energy of the reaction if the catalyst lowers the activation barrier by 20 kJ/mol
rate is constant so ...
k(normal condition) = k(catalytic condition)
=> Ea / Ea(cat) = T/T(cat)
=> Ea / Ea - ΔE = T/T(cat)
=> Ea/Ea-20 = 5/4
=> 4Ea = 5Ea - 100
=>Ea=100kJ.