The rate constant for the first order decomposition of a dcertain reaction is described by the equation
log_{10} k(s^{-1})=14.3-\frac{1.25\times10^4K}{T}
A) What is the energy of activation for this reaction?
B) At what temperature will its half life period be 256 minutes?
1rate = Ae-Ea/RT
lnk = lnA - Ea/RT
=> logk = logA - Ea/2.303RT
comparing the given eqn with the above one...
Ea/2.303R = 1.25E4
=> Ea= 2.303X8.314X1.25E4 J
half life = 256 mins = 256X60 s.
k = 0.693/[256X60]
wen we put this in the above eqn, we get T.
21Are v expecting the same level of tuffness for the questions ???
Sir, pl. reply!!!!!!!
A) 1.25*104 = Ea/2.303R
B) K = ln2 / 256*60
now sub. in given eqtn to get T
