1node so RHS is 0 as no e-
... possible only if r0 = 2a0 ..
The Schorodinger wave equation for hydrogen atom is
ψ\Psi_{2s}=\frac{1}{4\sqrt{2\pi}}\left(\frac{1}{a_0} \right)^{3/2}\left(2-\frac{r_0}{a_0} \right)e^{-r_0/a_0}
where a0 is the Bohr's radius, if the radial node is 2s be at r0 then find r0 in terms of a0
Easy dont get anxious.. This is a 2 marks question from JEE 2004
-
UP 0 DOWN 0 0 3
3 Answers
1hehe too easy for nodes probability of finding electron is zero
so
\Psi_{2s}=\frac{1}{4\sqrt{2\pi}}\left(\frac{1}{a_0} \right)^{3/2}\left(2-\frac{r_0}{a_0} \right)e^{-r_0/a_0} =0
so 2-r0/a0=0
hence r0=2a0