1Manish , replying after long time. :)
CH3NH2 (.1 mole.KB=5*10-4)is added to .08 moles of HCL and the solution is diluted to one liter.The resulting hydrogen ion concentration will be ________________
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2 Answers
1357CH3NH2+HCl→CH3NH3+ + Cl-
0.1 0.08
0.02 0 0.08
Kb=[CH3NH3+][OH-]/[CH3NH2]=0.08*Kw/(0.02*[H+])
[H+]=0.08*10-14/(0.02*5*10-4)=8*10-11 M
