1 M soln of a weak base BOH is only 0.5% ionised. If 2 ml 1 M soln of BOH is mixed with 30ml water, the degree of dissociation of the base in the resulting soln and H+ ion conc. of the soln will be ???
a) 0.02 and 1.25E-3
b) 0.02 and 8E-12
c)0.08 and 3.5E-3
d)0.04 and 3E-4
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2 Answers
Manish Shankar
·2008-11-27 08:26:18
The answer is coming (b)
Kb=(.5/100)2
M2=2/32=1/16
α=√(Kb/M2)=4*0.5/100=0.02
[H+]=Kw/cα=8E-12