1ya its correct.it appeared in jee-1998 u can check it out.
given
[Ag(NH3)2+]→Ag+ + 2NH3
kc=6.2x10-8
Ksp(AgCl)=1.8x10-10 at 298 K.
calculate the concentration of complex in 1 M aqueous ammonia
pls provide detailed solution
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4 Answers
62dude... i am not great at chemistry.. but this question to me is very unclear..
where do we get Cl concentration??!!!
Are u sure this is the right question... it may be.. but as i said i am not perfect (not even close!)
1[Ag(NH3)2+]→Ag++2NH3
C-x x+y 2x
AgCl=>Ag++Cl-
x+y y
Kc=(x+y)*(2x)2/ (c-x)=k1
but NH3 concentration=1
hence 2x=1
further
Ksp AgCl=(x+y)(y)=k2
as x is known we can obtain y from the above eqn
k1=(x+y)(2x)2/c-x
as x,y,k1 are both known
we can obtain c