ionic equilibirium

200ml of HCL(aq.) havin ph=2 is mixed with 300ml of NaOH(aq.) having ph =12. concentration of OH-1 in the mixture will be x *10-3, mole/l. value of x is..?

a. 1
b. 2
c. 3
d. 4

1 Answers

1357
Manish Shankar ·

[H+]=10-2
[OH-]=10-2

mmol(meq) of base=300x10-2=3
mmol(meq) of acid=2

mmol of base remains unreacted=3-2=1
total volume=500 ml

[OH-]=1/500=2*10-3

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