200ml of HCL(aq.) havin ph=2 is mixed with 300ml of NaOH(aq.) having ph =12. concentration of OH-1 in the mixture will be x *10-3, mole/l. value of x is..?
a. 1
b. 2
c. 3
d. 4
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1 Answers
Manish Shankar
·2009-11-11 19:56:17
[H+]=10-2
[OH-]=10-2
mmol(meq) of base=300x10-2=3
mmol(meq) of acid=2
mmol of base remains unreacted=3-2=1
total volume=500 ml
[OH-]=1/500=2*10-3