See, 50% neutralization means that conc. of NH4OH and NH4Cl is the same. Therefore,
pOH = pKb + log[salt][base]
=> pOH = pKb
pH = 14 - pOH
pKb of NH3 is 4.74. The pH when 100ml of 0.01 M NH3 solution is 50% neutralised by 0.01 M HCL is
plzz explain
See, 50% neutralization means that conc. of NH4OH and NH4Cl is the same. Therefore,
pOH = pKb + log[salt][base]
=> pOH = pKb
pH = 14 - pOH
Is it 9.26?