Determine molar solublity of AgSO4 in 0.25M Na2SO4 solution and determine the factor by which soolublity decreases when it is compared to solublity in pure water.Ksp=1.4*10-5 at 25°C
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1 Answers
Manish Shankar
·2008-11-13 12:35:39
initially let solubility be S
then S*0.25=1.4*10-5
S1=5.6*10-5
solubility in pure water S2=√Ksp=0.00374
S2/S1=67 times