42) [Sr2+][F-]^2 = 7.9* 10-10
=> [Sr2+] = 7.9* 10-10/ (3.7*10-2)2
= 5.77 * 10-7
[Sr2+][CO32-] = 7*10-10
=>[CO32-] = 7*10-10 / 5.77 * 10-7
= 1.213 * 10-3
1) a weak base BOH is titrated with st acid .The pH at 1/4th equivalence point was 9.24.Enough strong base(6 meq) was now added to completely convert the salt.the total voume was 50ml.find pH at the point
2)A soln is saturated wrt Strontium flouride and strontium carbonate.the flouride ion conc. in soln is found to be 3.7*10-2 mol/LWhats the value of [CO32-] ??
Ksp(SrF2)=7.9*10-10
Ksp(SrCO3)=7*10-10
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2 Answers
4
13571.
pH=pKa+log(salt/acid) for acid
pOH=pKb+log(salt/base)
(salt/base)=1/3
find pKb from here
At the end point salt formed is B-
which will hydrolyse and so find the final pH
