An experiment requires minimum beta activity product at the rate of 346 beta particles per min.The half life period of 99Mo42,which is a beta emitter is 66.6 hours.Find the minimum amount of 99Mo42 required to carry out the exp in 6.909 hrs.
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1 Answers
62THis seem simple
find k
Also find the amount of Mo at the end of 6.909 hrs using activity of 346beta per min
ie taking k[A]
Important thing to keep in mind is that half life is in hours while the activity is given in per minutes.. so make sure you have taken care of that too...
Also once you have foudn the amt of Mo at the end of 6.909 hrs, you can do the same at the beginning of the eperiment
