1i too think so.
What is the order of lattice energy evolved during the formation of the following ionic compounds from their respective ion pair in gaseous state?
MgO, CaF2, LiF
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3well i have found dat Li has lesser ionic radii than that of calcium in wikipedia.sry for confusions.
1ya,that might be a reason as the size differing by one shell.i actually didn't link these two.just applied the born-lande's concept.k.lets see.
106he said to consider charge density... then Li+ would have greater charge density than Ca2+
1From the Born-Landé equation it can be seen that the lattice energy of a compound is dependent on a number of factors :
i) as the charges on the ions increase the lattice energy increases (becomes more negative),
ii) when ions are closer together the lattice energy increases (becomes more negative)
obviously , LiF has less lattice energy than oder two wid respect to 1st point.
now, Ca+2 is having a larger ionic radii than Mg+2 , thus wid respect to 2nd point , MgO > CaF2.
thus, the order is what asish hs given.
106this was BT question and they have given the answer as MgO > CaF2 > LiF
for the reason they have just given the lattice energy values :(
1@msp is this written in jd lee that Ca2+ have smaller ionic radii than that of Li+.
3http://en.wikipedia.org/wiki/Born-Land%C3%A9_equation
i have read this in jd lee.but for reference u can see the above link.