1Use formula BM=√N(N*2)
where n is no of unpaired electrons.
The spin only magnetic moment value( in Bohr Magneton units ) of Cr(CO)6 is
A) 0 B) 2.84 C) 4.90 D) 5.92
( ANSWER THE QUESTION WITH EXPLANATION )
-
UP 0 DOWN 0 1 2
2 Answers
29Ans A...config of Cr 4s13d5..since CO is a strong field ligand..so all the electrons will be paired to generate two 3d and one 4s orbital for hybridisation
