continuing from debosmit's post,
4.moles of Al = 3.moles of O2
or, 4*21/27 = 3*x/32
or x= 128*7/27 = 33.18 gm
what is the mass of oxygen that will react with 21 gm of Al?
continuing from debosmit's post,
4.moles of Al = 3.moles of O2
or, 4*21/27 = 3*x/32
or x= 128*7/27 = 33.18 gm