write the equation....
CaCO3→CaO+CO2
mass of CaCO3 used=10 g
Actual mass of CaCO3 used=9g....(90%)
Thus,moles of CO2=9100 mole
Volume at NTP=9x0.224 L =2.016 L...what is the correct answer??
Find the volume of CO2 at NTP obtained on heating 10 gm of pure 90 % pure limestone
how to proceed?
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1 Answers
Anik Chatterjee
·2012-06-12 03:01:09