nice one

8 Answers

1
°ღ•๓яυΠ·

isse bhi dekh lo bhai

13
Двҥїяuρ now in medical c ·

second one 6.1....

[(14-11.6)+9.8]/2

13
Двҥїяuρ now in medical c ·

is the first one D

1
°ღ•๓яυΠ·

i dunno d answers
post ur method

1
°ღ•๓яυΠ·

koi toh bata bhi do ..sharmao mat

1
°ღ•๓яυΠ·

abhirup plez gimme d sol

13
Двҥїяuρ now in medical c ·

i ve done the 2nd one...#4

1357
Manish Shankar ·

for I
(+ -)+H2O→(-)+H3O+

Ka given is 1.6*10-10

Kb=Kw/Ka=10-14/1.6*10-10=6.25*10-5

For second

As it exist as zwitter ion in solution

pH=[pKa(NH3+---)+pKa(-COOH)]/2=[9.8+14-11.6]/2=6.1

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