isse bhi dekh lo bhai
second one 6.1....
[(14-11.6)+9.8]/2
is the first one D
i dunno d answerspost ur method
koi toh bata bhi do ..sharmao mat
abhirup plez gimme d sol
i ve done the 2nd one...#4
for I(+ -)+H2O→(-)+H3O+
Ka given is 1.6*10-10
Kb=Kw/Ka=10-14/1.6*10-10=6.25*10-5
For second
As it exist as zwitter ion in solution
pH=[pKa(NH3+---)+pKa(-COOH)]/2=[9.8+14-11.6]/2=6.1
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