pH

Calculate pH of a 0.016M aqueous solution of Ca(CH3COO)2 .Ka=2*10-5

2 Answers

1357
Manish Shankar ·

Ca(CH3COO)2 will break as Ca2+ + 2CH3COO-

so hydrolysis can be written as

CH3COO-+H2O [eq] OH-+CH3COOH

pH=-(1/2)[logKw+logKa-logc]

here c is the concentration of CH3COO-=2*Ca(CH3COO)2=0.032

24
eureka123 ·

thanx sir.........

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