thanx sir.........
Calculate pH of a 0.016M aqueous solution of Ca(CH3COO)2 .Ka=2*10-5
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2 Answers
Manish Shankar
·2008-11-01 06:21:32
Ca(CH3COO)2 will break as Ca2+ + 2CH3COO-
so hydrolysis can be written as
CH3COO-+H2O [eq] OH-+CH3COOH
pH=-(1/2)[logKw+logKa-logc]
here c is the concentration of CH3COO-=2*Ca(CH3COO)2=0.032