ph increases by value of log3
Whatr is ph of 1L buffer containig initially 0.02 mol NH3 and 0.02 mol NH4Cl after addition of 0.01 mol of NaOH? (Ignore volume change).pKa NH4+=9.24
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5 Answers
Manish Shankar
·2009-01-11 09:48:25
I m also getting log3
pH = Pka +log [(NH3)/NH4+)
pH1=pKa
pH2=pKa+log(0.03/0.01)=9.24+lpg3=9.24+0.48=9.72