PHYSeCAL....

10 Answers

39
Dr.House ·

wats your doubt?????????? or u wanted to show us the questions? i will try to slve

33
Abhishek Priyam ·

he need soln of both the questions thats it.... thats why he posted....

1
MAGIC MATH ROCKS ·

LOL....
yeah PRIYAM is spot on!!!

I wud like to know the soln of both......

First one looks pretty simple but sumhow I'm not gettin da ans :(

1
MAGIC MATH ROCKS ·

hope the image is clear enough.......

waitin 4 answers pl. help...........

62
Lokesh Verma ·

C2H4 needs 3 moles of O2

I think it should be (226/1411)*3*22.4 litres.. which seems to be none of these :(

But the problem here is that it is not specified if the heat is in KJ/mole or KJ/kg or what..

62
Lokesh Verma ·

Not even close to sure on this one.. but what i have done:

4 l of Oxygen is released when 8 liters of Hydrogen gas is released (This is only due to water's electrolysis)

(3.2/22.4) moles of H2

so 3.2/22.4 moles of H2S2O8

mass of 1 mole of H2S2O8 = 2+64+128=194. g

194x .14285=27.7

1
MAGIC MATH ROCKS ·

Bhaiyan by ur Mida's touch u hav got da ans spot on!!!

I jus had a doubt that wat is the significance/meaning of "11.2ltr of H2 wer produced at NTP"

Wats the interpretation we cud derive frm it???

62
Lokesh Verma ·

in the second one it is the total H2 released

out of this, some of it will be due to electrolysis of water.

that will yield Oxygen as well.

If we compensate this then we will get the hydrogen actually got from the electrolysis of our concern :)

62
Lokesh Verma ·

first one I am think that there is some mistake in the options :(

1
MAGIC MATH ROCKS ·

has 2 b coz 296litre is tooo huge 4 convinience........

....ok so that H2 was jus an indication of water electrolysis!!!! otherwise its exact value didnt hav 2 do much wid da questn

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