A bottle contains 1 mol He(g) and second bottle contaisn 1 mole Ar(g) at the same temperature.At this temp. ,the rms of HE is 1477 m/s and of Ar is 467 m/s.What is the ratio of no. of HE atoms in 1st bottle to the no. of Ar atoms in 2nd bottle having these speeds.Assume both gases are ideal.
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1 Answers
tapanmast Vora
·2009-02-02 22:52:56
Vrms = √(γnRT/MM)
compare the ratio of given speeds with da inverse root ratio of their molecular masses
now u can then get the ratio of mols, then easily the no of atoms......
plz reply if u get da ans by this meth