11dekh bhai d=m/v and M =n/v
or M=m/(Mol massXV)
or M=d/Mol mass
the density of a 3.60 M sulphuric acid solution that is 29% H2SO4 by mass will be ??????????????????????????????????????
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10 Answers
1yaar ye simple hai............. lekin mera answer match nai kar ra... asked in aieee. my one is 1.22
but given is 1.64 in g/ml
1?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
1let density be d gm/lt.
then in 1000ml, mass of soln = d gm.
29% h2so4 so....
100gm soln has ... 29 gm h2so4
1gm has .............. 29/100 gm.
d gm has ...............29 d/ 100 gm
so, in 1000ml,
mass of h2so4, 0.29d gm.
now, mol mass = 98.
so, molarity = 0.29d/98X1000
= 3.60 (given)
=> d = 1.216
[i dun think its wrng... its a simple prob ... but its chem! so plz correct me if i am...
btw, aman, if u have taken this q from arihant ... it MAY have wrong ans :P ]
