as no. of atoms in f.c.c.=6*1/2+8*1/8=4
so no. of octahedral voids=4
and no of tetrahedral voids=2*octahedral voids=2*4=8
so,
clearly
x=4
y=8
1) every atom or ion that forms an fcc unit cell is surrounded by x octahedral holes and y tetrahedral holes.?where x and y are..............
2)consider the structure of CsCl(8,8 coorsination).How many Cs+ ions occupy the second nearest neighbour locations of a Cs+ ion ?
as no. of atoms in f.c.c.=6*1/2+8*1/8=4
so no. of octahedral voids=4
and no of tetrahedral voids=2*octahedral voids=2*4=8
so,
clearly
x=4
y=8
trying,and a similar question was posted by kamalendu in his RESO JPT3
thread which i could not get.
for second it should be 8.(since it is a simple cubic structure)
answer to the 2nd 1 is 18 surely
think 3d
shayad isse kuch samajh aa jaye