Mg(OH)2≈Mg2++2OH-
And at pH=12,,there will be predominantly OH- ions...use this and get the answer
The solubility of Mg(OH)2 (Ksp = 10-12) in solution of pH value 12 is
1. 10-8
2. 10-6
3. 10-5
4. 10-10
Mg(OH)2≈Mg2++2OH-
And at pH=12,,there will be predominantly OH- ions...use this and get the answer
at pH = 12 conc. of OH- = 10-2
Mg(OH)2 == Mg2+ + 2OH-
1-s s 2s+10-2
Ksp = [Mg2+][OH-]2 = s*(2s+10-2)2
As s<<10-2
So, s*10-4 = 10-12
=> s = 10-8