SOLUTIONS-3

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(1) Sea water is found to contain 5.85% NaCl and 9.50% MgCl_₂ by weight of solution. Calculate its normal boiling point assuming 80% ionisation for NaCl and 50% ionisation of MgCl_₂[K_b(H_₂O) = 0.51kgmol^-1K].

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govind ·2010-01-19 00:10:10

in this question we have 0.1 mol of NaCl and 0.1 mol of MgCl₂ in around 85g water
on 80% dissociation 1 mol of NaCl will produce 1.8 moles
and on 50% dissociation 1 mol of MgCl₂ will produce 2 moles
so we have 0.38 moles in 85g water
molality = 4.5
âˆ‚T = 4.5 * 0.51
=2.29
so sea water will boil at 102.29 C

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UTTARA ·2010-01-19 00:52:19

I dint understand this part

" in this question we have 0.1 mol of NaCl and 0.1 mol of MgCl2 in around 85g water
on 80% dissociation 1 mol of NaCl will produce 1.8 moles
and on 50% dissociation 1 mol of MgCl2 will produce 2 moles "

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