using
ΔTf = i X Kf X m
0.558= i X 1.86 X 0.1
u get i=3
so formula should be :
[Co(NH3)5Cl]Cl2 so that total no of particles is 3
(1) A complex is represented as CoCl3 . x NH3 . It's 0.1 molal solution in aq.solution shows ΔTf = 0.558°C. Kf for H2O is 1.86 K mol-1kg. Assuming 100% ionisation of complex and coordination no. of Co is six, calculate formula of complex.
using
ΔTf = i X Kf X m
0.558= i X 1.86 X 0.1
u get i=3
so formula should be :
[Co(NH3)5Cl]Cl2 so that total no of particles is 3
I dint understand this part
u get i=3
so formula should be :
[Co(NH3)5Cl]Cl2 so that total no of particles is 3
i=3 means that the number of particles in aqueous solution is 3.
So, in
[Co(NH3)5Cl]Cl2 , 2Cl- and one [Co(NH3)5Cl]2+ are produced, so that net no of particles is 3.