1
Bicchuram Aveek
·2009-11-04 22:55:52
Kx is the equilibrium constant w.r.t the mole fractions of each substance at equilibrium.
Kp = Kc(RT)Δn
Kp = Kx pΔn
1
Jagaran Chowdhury
·2009-11-05 01:37:07
N2 + 3H2 = 2NH3
a b 0
a-x b-3x 2x
KC = ( 2x/500)2
____________
(a-x/500)*(b-X/500)3
TOTAL NO OF MOLES AT EQ.= (a+b-2x)
TOTAL PRESSURE AT EQ= (a+b-2x) R 400
__________
500
PARTIALL PRESSURE OF N2=(a+b-2x)*R*400*(a-x)
____________________
500*(a+b-2x)
SIMILARLY, FIND PARTIAL PRESSURES OF OTHERS AND FIND KP. IT WILL BE FREE OF (a+b-2x).SO CAN BE COMPARED TO KC
1357
Manish Shankar
·2009-11-05 03:17:10
Kx is not a fixed quantity. It depends on the total pressure of the system.
So for the reaction, we can't tell unless the total pressure is given
1
Jagaran Chowdhury
·2009-11-05 03:28:46
sir but wont the pressure at equilibrium depend on the state of eq,(i mean a+b-2x) which will be constant for a particular value of equilibrium constant .the pressure is found out using the other conditions at eq
1357
Manish Shankar
·2009-11-05 03:30:34
yeah it is
but in this case we don't know a and b also
1
Jagaran Chowdhury
·2009-11-05 03:34:57
dont need to know that. kp /kx is coming out to be a fixed quantity