TPQN 28

AIEEE 2015 Online › Physical Chemistry questions › TPQN 28

In the given reaction at 300K
C₆H₆ + 15/2O₂---------->6CO₂ + 3H₂O enthalpy= -3271kJ
What is change in the internal for the combustion of 1.5 mole of benzene at 300K?
a)-3267.25kJ
b)-4900.88kJ
c)-4906.5kJ
d)-3274.75kJ

#Chemistry #Physical Chemistry

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5 Answers

Rohan Ghosh ·2008-12-14 07:04:25

i think the enthalpy is given per mol
then the answer just
-1.5*(3271)=-4906.5

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Aakash Sharawat ·2008-12-14 16:35:36

bingo! i too got the answer same as your answer!
well i am sorry to say that according to the answer key the answer is b!!!!!!!!!

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1357

Manish Shankar ·2008-12-14 20:50:18

I think you have to consider Î”nRT part

Î”H=Î”U+Î”nRT

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Aakash Sharawat ·2008-12-17 16:22:35

@manish: bhaiya by using this we are getting -3659KJ which none of the options above! i think that they must have given the wrong answer!

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skygirl ·2008-12-17 21:01:56

the ans should be 'c'.
no explanation given in the answer key in support of b ??

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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TPQN 28

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