vapour pressure...Ques

Q1 there are many things missing which must be given in the question
it must be mentioned if the solutes are volatile or non volatile also density of water at 75°C must be given
let density of water given at this temp = d
also molar mass of solute is also necessary
for non volatile solutes:

vapour pressure of solution= p°x₁
p°= original vp of solvent(water here)
x₁= mf of solvent

now p° value for water at ntp/stp(25°C) is about 0.0263atm
using the formula:

ln(p₂p₁)=
H_v2.303R(T₂-T₁T₂T₁)
we can find vapour pressure of water at 75°C if we know the heat of vapourisation H_v of water
for calculating mf--> x₁
molar mass of solute is required

Q2
molarity = 0.00351
molality = 0.0091

i think in the first ques she wanted to ask lowering of vapour pressure but evven then im confused....