30I'm unsure whether the whole of this energy is manifested in the form of K.E. If it so, then the task of finding the wavelength shouldn't be difficult!
8 Answers
1E=hcλ
150×16×10-19=6.626 × 10-34×3×108λ
λ=6.626 × 10-34×3×108150×16×10-19
λ=82825×10-10 m
1@nishant sir: i think λ should be less than the value which has been obtained in the 2nd post because of the work function........
30
62WHere did work function come from!!!! :O
this is about particle nature and wave nature.
Think about an electron and its energy! why will the electron have enrgy?
and also think of when hc/λ is valid?
1for an electron in an atom....we know that the ratio of the potential enegry and kinetic energy is 2:1....
hence,1/2mv2= 1/3x150=50eV....
we know the mass of an electron....so we can find out the velocity....
hence λ=h/mv....i`m nt sure if the method is correct....pls verify
21Electrons revolving around the nucleus also have energy but do they have wavelength? I am not sure about the answer. So please answer me.
