49so h=-R+√(4R2+1)/2≈0
bt u said dat we will b shocked 2 see the answer....n this is obvious...
21Sorry [2]
if u want , i will delete it [1]
62there is a solution to the thing on the net to every question in the world i guess :P
But try to avoid arbitrary google search.. it is nto going to help you. Not at all. Sorry if i am being rude.. you should try these questions on the book not on google search :D
21
omkar
·2010-05-19 23:07:18
actually i got this soln from the net , but skipped some calculation part
62
Lokesh Verma
·2010-05-19 22:36:02
not a very difficult one.. but how did you get the final result?
21
omkar
·2010-05-18 02:35:21
In the diagram below, the belt meets the Earth at a tangent, and therefore the angle between the belt and a radius is 90°. Consider two lines: one joining the center of the Earth to the high point of the rope; the other joining the center of the Earth to one of the points at which the belt meets the Earth. Let x be the angle subtended, in radians, between the two lines. Let a be the distance from the high point of the rope to a point at which the belt meets the Earth.
For d = 1, r = 6,400,000, we obtain h =121.6 meters.
1um ..
I was thinking all the time that it was a physics question.
62
Lokesh Verma
·2009-11-20 05:48:34
{(θ R + 1)/2}2 +R2 = (R+h)2
and
tan θ/2 = {(θ R + 1)/2}R
Now can you solve these?
62
Lokesh Verma
·2009-11-20 05:34:44
no the answer is atleast a few hundred times more than 1 meter (did i say atleast?)
24hmm
so i was wrong...
I had a bad feelign abt that ....[3][3]
btw just wondering if this ques is related to ques here
http://targetiit.com/iit-jee-forum/posts/gud-combination-of-concepts-1992.html
I mean anything to use ???
1yup ! AO = OC but not equal to 1/2 .
62
Lokesh Verma
·2009-11-11 07:32:25
lol.. read post 11 for clarification of what is 1/2 ;)
1But y is it not half????[7]
We can consider two tangents to be drawn from point O at A and B.
So AO=BO=1/2...
Sorry if its a stupid question!![14]
62
Lokesh Verma
·2009-11-11 03:26:36
but what eureka has done is incorrect..
That length is not half!!!
3it seem to me a rolling motion.Or the earth is rotating abt the pt of contact of the thread which is vertical.
24
eureka123
·2009-11-11 02:30:21
i assumed AOC=1m
so AO=OC=1/2
62
Lokesh Verma
·2009-11-11 00:30:08
The radius of the earth is not changing..
The belt is being pulled so that it is not slack..
So there will be a height .. The question is to find that height..as shown by eureka in post 6 (diagram)
21sir can u jus see wats wrong with ma answer.......may be i may not to able to understand the q properly
62
Lokesh Verma
·2009-11-11 00:23:56
yes Dc you are on the right track.
You guys will be surprised to see the right answer ;)
1
Divesh
·2009-11-10 22:11:15
Sir u hv told that the wire is 1 m extra in length ..
So isn't it that
[ AO+OC] - [Lenght of arc AC ]= 1 m
[See euro's diagram ]
62
Lokesh Verma
·2009-11-10 21:53:46
Sorry my mistake.. it is AOC... (The diagram I made had a small issue :( )
THat is why you guys got confused
23i think nishant sir has said dat
length\; of\; wire\; = 2 \pi (64 \times 10^{5} ) + 1
24
eureka123
·2009-11-10 18:26:17
approach like this ???
plz confirm sir...
