On an island there are 5 pirates {A,B,C,D,E} who are equally greedy and equally logical. They have 1000 coins and they have to distribute it among themselves. First A gives his plan for distribution. If his plan is accepted by majority, then his plan is accepted or else he is thrown into the sea. Then B will give his plan and so on. What must be the plan of A such that his plan is accepted?????
No of pirates Majority
5 3
4 2
3 2
2 1
1alok! three are satisfied! so, why would dey throw him(A) in da sea!!! [4][3]
1I cant understand. its ok if u think reverse, but what if u think straight. A will b murdered by his companions...
1soumik, u r nt getting da grip of dis ques!!
dey are pirates.... nd dey are vry vry greedy! but logical as well....
see, one pirate wont care abt da others.. he would only want a maximum share which he would get if he satisfies the required no of folks! he did dat and so he wsnt thrown out!!!!!![4]
well, dis is just a way of telling u...!! [3] the question had choices.. and 200,200,200,200,200 wasnt a choice!!!! [3][3][3]
11But with that B,C,D,E will disagree as they will be getting <200 coins!
1soumik, why would a greedy person go for 200 coins when he is getting 998!!!!??? lolzz.... [3][3][3]
11Shreya - now see.....
Having considered all those possibilitites that u've mentioned, the pirates see, that 1 will get the max share while others only get to share the rotten bits of 0 and 1 coins....so they should decide that the only acceptable plan is to have equal shares of 20 coins each, and thus majority of them shuld disagree with A..... - seeing the plan that A's planning 2 give!
1the question is very simple if you think logically!!!
Think reverse...
Let only D and E are there( and rest had been thrown) then,
D will keep 1000 coins with himself and give 0 to E, since out of 2 only 1 has to be satisfied.
D→1000, E→0
Now Let C is also dere.Then C has to satisfy 2 ppl. So he will keep 999 with him, give 0 to D and give 1 to E. (They will follow this plan because if E disagrees he will get no coin with D.. so its better to take one coin than none...!!![4]).
C→999, D→0, E→1
Now Let B is also dere. Then he again has to satisfy 2 ppl. So he will keep 999 with him, give 0 to C, give 1 to D and 0 to E. (They will follow this plan as here D gets one coin... he is happy to get one coin with B than none with C!!).
B→999, C→0, D→1, E→0
Now Let A is also dere. Then he has to satisfy 3 ppl now. So he will keep 998 with him, give 0 to B, 1 to C, O to D and 1 to E.
(this will make C and E happy who get o coin with B's plan.!)
So, A→998, B→0, C→1, D→0, E→1
Hope u got it now... [1]
1i am sorry ..i am posting the answer very very late [didnt checked this post..!!]
the answer is
A 998
B 0
C 1
D 0
E 1.
62yes gaurav.. you are right..
i think i had solved this one many years back..
i remember distinctlly that B=E=0
and one of the guys was to get somethign close to 999 :)
so yeah i think you are right.. the logic.. again after a lecture of 6 hours, i dont have enuf in me to think :D
1i dont think so first i want to know whether my ans is right or not then i will explain it
1my solution
A--997
B--0
C--1
D--2
E--0
value for A is max and for B and C is min ( least for they can agree )
plz do comment
@Nishant lion kabhi budha nahin hota
1budha "go" gaya hoon....i also think the same for u :D.......SORRI
62I think I remember this one..
1, 0, 0, 999, 0
Not sure but yeah there was all this back calculation that I cant do.. (budha go gaya hoon :D)
1no!!
he wont like to be thrown in the sea....
i'll give u a hint...
think reverse....[start when u hve only D and E and do keep in mind that they all are equally greedy and equally logical]
