01-03-09 Googly from Resnick!

This is a googley from resnick and halliday..

Those who can will do it in a flash otherwise keep thinking for the whole day and you wont get it ;)

Find the maximum heap (Height) that sand can make in a circle of radius of R.

Coefficient of friction of sand is k.

I dont have resnick with me.. but i did it when i was preparing for JEE. I remember this question cos I was ecstatic when I solved this one ;)

41 Answers

1
skygirl ·

woh toh abhi sochte hai :P :P :P

1
skygirl ·

like .. k= tanθ = h/R

so... h=kR.

[actually this k always happens to come out tanθ .. ]

62
Lokesh Verma ·

@ sky.. what's the logic
@ philip: :D
@ gaurav: no.

9
Celestine preetham ·

donno abt this but i feel its impossible unless k>=1 ??????????

9
Celestine preetham ·

super tukka sky ;)

62
Lokesh Verma ·

celestine did u get the question..

62
Lokesh Verma ·

@ sky this tukka always works but just be a bit careful..

sometimes it is 1/tan theta also ;)

9
Celestine preetham ·

yes i took this analogous to pressure due to water

so that the pressure of friction = pressure of water

so that k >= 1

i may ve gone crazy

62
Lokesh Verma ·

I think you have this time :D

sky's answer is correct

@celestine.. do you think friction is that high ever?

k is generally .1 to .5

so according to you we will hardly be able to make a heap of sand!

1
skygirl ·

sure bhaiya... yeah sometimes it betrays .... but then... its 'kabhi kabhi' only...

62
Lokesh Verma ·

ok..

but then how do we solve this one without tukka?

1
Philip Calvert ·

strong feeling :D :D

1
skygirl ·

and yeah,,, sorry to all tiit-ians for my tukka [17]

9
Celestine preetham ·

okk now got it
i was considering k btw floor and sand ;(

now use mgsinθ = kmgcosθ for a sand particle along slope

9
Celestine preetham ·

and bhaiyya theoretically wat i said was right i think

ie k btw floor and sand >=1

wen we consider that it behaves as a fluid this follows

62
Lokesh Verma ·

are u sure celestine?

Think again..

Think of it likethis.

what are the horzontal force on any particle on the floor which friction needs to balance out??

33
Abhishek Priyam ·

hey!![1]

this q was earlier asked.. and i gave the answer[1]..

http://targetiit.com/iit_jee_forum/posts/resnic_halliday_problem_140.html

33
Abhishek Priyam ·

what is most imp is that... ans is tanθ

62
Lokesh Verma ·

yup.. exactly :)

1
chemistry organic ·

yes, i have also thot the same answer.....yipeee

9
Celestine preetham ·

#37

yes i think

the outer most particle will have unbalanced pressure

62
Lokesh Verma ·

@gaurav.. still simpler ;)

62
Lokesh Verma ·

check the language now..

1
gagar.iitk ·

R{(1-k2)1/2-k}/(1-k2)1/2

1
gagar.iitk ·

Those who can will do it in a flash the statement is suggesting the ans is R but i am not getting it

62
Lokesh Verma ·

umm.. no..

and at k=0, when there is no friction then all sand should just slip.. so at k=0, height should be 0.

62
Lokesh Verma ·

haha.. you are pretty close to the answer in #5.. but there is slightly more to it ;)

11
Mani Pal Singh ·

arrey k ka bhi to use karo
but thinking[12]

1
gagar.iitk ·

then in that case some calculation mistake b'cos previously i was getting

at k=0, when there is no friction then all sand should just slip.. so at k=0, height should be 0.

1
gagar.iitk ·

R(1-cosx) tanx=k

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