06-10-09 Trigonometric Summation

Find the sum of the infinite series...

sin^3x+\frac{sin^33x}{3}+\frac{sin^33^2x}{3^2}+\frac{sin^33^3x}{3^3}+...

(Hint recall the questions I have given during the last few days...)

9 Answers

1
xYz ·

did it using........
sin3x=(3sinx-sin3x) /4

62
Lokesh Verma ·

Did I say that this is an infinite series?

btw what you have done is correct.. :)

You killed this one.. (I had thought that this would not be solved this simply.. May be I have repeated the idea a bit too often now ;)

23
qwerty ·

@ nishant sir y arent u replying to my queries nowadays

62
Lokesh Verma ·

@Qwerty.. am I not.. even if it is, It is purely unintentional.. (sorry if that is happening.. but with so many requests for answers i miss a lot of them)

23
qwerty ·

kk....jus jokin ....but i had posted u a few questions in ur scrapbuk earlier ....but they are cleared now .......but yeah ..i wil be coming wid de new ones!!

3
msp ·

if xyz's ans is correct for n terms then the rest is simple we have to apply the limits that n tends to infinity

so S∞=3/4sinx

62
Lokesh Verma ·

Yup it is correct.. i was just pointing out that he missed out that small thing .. [1]

3
msp ·

yes i just want to finish up,since i din ever finished a qod :P

62
Lokesh Verma ·

Dont worry you have enough time to improve.. and you are getting close to doing that :)

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