190∫∩/4 log(sin x)dx =-∩/4 log2 ......now its simple integration by parts,,,
u=sin x and v=log(sin x)
Find the integral
\int_{0}^{\pi/4}{\sin x \times \log(\sin x)dx}
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9 Answers
1is the integral defined i mean log(sinx) will be undefined when x is zero
1i guess it will be an improper integral.....u hav to find limits tending to 0 after doing by parts....and solve
191u cannot do it by parts the integral is not defined when x tends to 0
106it is not defined at zero no doubt but it IS defined at 0+. So the integral is essentially 0+∫pi/4-