11-03-09 Unique Sequence

Given x0>0 and a>0, show that there exists one and only one sequence {x0, x1, x2,...) such that x_n = \sum_{j=n+1}^{\infty} x_j^a

22 Answers

1
Akand ·

well i think...............take two sequences..........
Xn=A...........and also Xn=B........
after doing sum mathematical stuff............
try to get A=B...........
thts all
by dis we can show tht it is unique.............

21
Shubhodip ·

sir is that okay?

21
Shubhodip ·

yes sir k is a function of m and n but it is always greater than zero for all m,n>0 this was true only if a is a positive integer..

by the way hope this will suffice..

if we prove f(x)= x+ xa is monotonic for all x>0 (where a is a positive real number) then also we prove that x(n+1) is unique...f"(x)>0 for all x>0

62
Lokesh Verma ·

there is one small problem shubhodeep..

it is not very clear why x-y is a factor of x^a-y^a..

since a is any real number not an integer... and what is the guarantee that the other factor k whihc you have taken is not zero for any m and n which are not equal

(since k is not a constant but a function of m and n!)

21
Shubhodip ·

Giving a try to this one...

x(n)=Xa(n+1) + xa(n+2) ......

x(n+1) = xa(n+2)....

so x(n) = x(n+1) + xa(n+1)

as prophet sir said, if we prove x(n) obtained from this relation is unique we r done..

so we have to prove that the function f(x)= x + xa does not take same value at two distinct points in its domain...at least for x>0 because we have x(j)>0

to prove that by contradiction method lets take two distinct point m and n in its domain (m,n>0) for which we hace f(m)= f(n)

so we have m-n + ma - na=o

or (m-n)(k)=0 (where k>0 as m,n>0)

only possibility m=n

so this is one-to-one function...so proved...

62
Lokesh Verma ·

neone trying this one?

341
Hari Shankar ·

Well priyam has written x_n = x_{n+1} + x_{n+1}^a

Now, if we prove that xn+1 obtained from this relation is unique, we will have established that the sequence is also unique.

So, now consider the function f(x) = x + x^a

Is there a way to prove that this function is one-one?

11
Mani Pal Singh ·

iss ko aadha hi choodna hai kya

62
Lokesh Verma ·

Akand you have given a very good reasoning..

try to go ahead and prove what you said.. you are quite close :)

33
Abhishek Priyam ·

aur kuch nahi samajh aa raha abhi... :(

33
Abhishek Priyam ·

If Xn+1 is unique then Xn is unique.. so have to show x∞ unique.... (lekin x∞ ... :P)

341
Hari Shankar ·

wow! absolutely correct sir. (I think I am now justfied in calling you sir)

62
Lokesh Verma ·

so how do you prove uniqueness?

You have solved it 50% already

33
Abhishek Priyam ·

Xn=Xn+1+(Xn+1)a

33
Abhishek Priyam ·

acha..

62
Lokesh Verma ·

write xn+1 in terms of xn

33
Abhishek Priyam ·

nahi ban raha... :(

39
Dr.House ·

how to prove that a sequence is unique? gimme a hint and i think i can carry off

62
Lokesh Verma ·

Guys .. try this one..

it is a wonderful question..

1
MATRIX ·

but no answers ..........

1
Akand ·

i cant understand............who is correct?

62
Lokesh Verma ·

haha :)

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