19th December 2008

|y|= |sin x|

Plot the graph and also find the area in the region (0, 2 π)

*Backlog clearing question of the day!

52 Answers

1
greatvishal swami ·

1
Akand ·

|y|=sinx....................isnt it same as |y|=|sinx|............then if its not...............it must hav d graph of a half wave rectifier.........only d top part will be shown......

62
Lokesh Verma ·

No akand..

This is nto the right inference!

1
Akand ·

ok...........ill w8 4 d correct answer 2 cum..................till then ill try 2 brainstorm hehe

1
Akand ·

ok sorry tht will be a full wave rectifier.................

1
Akand ·

I hope thts correct..........

62
Lokesh Verma ·

umm..

Hint: It will not exist at a lot of places!!

So the grpah will have "gaps"

11
Anirudh Narayanan ·

graph of lyl=sinx?

62
Lokesh Verma ·

yup aragon

1
Akand ·

will it exist only at 50% places and not at 50%??????......Sharp 50%???

62
Lokesh Verma ·

FIrst graph is y=sinx Alternating current

2nd graph is y=|sin x| Full wave rectifier

What we want is

|y| = sin x !

Just think it over!

11
Anirudh Narayanan ·

lyl=sinx

62
Lokesh Verma ·

Yup aragon.. this is good :)

Good work for |y|= sin x

1
Pavithra Ramamoorthy ·

dats y i said adjus wit dis.........i did it in paint................... was lazy n so put i strgt

62
Lokesh Verma ·

no vishal it is only true for

|y| = sin x

Not for

|y| = |sin x|

11
Anirudh Narayanan ·

For lyl=lsinxl,

1
RAY ·

kitna simple tha.......btu bro plz foto uploading fast karo nah.......

1
dimensions (dimentime) ·

is this the right graph :

11
Anirudh Narayanan ·

Already posted

1
dimensions (dimentime) ·

sorry, some else has already posted,

late in posting...............

1
greatvishal swami ·

hey i m nt some else i atleast hav a name :D

1
tushar malik ·


is this graph right for |y|=sin x

62
Lokesh Verma ·

no tushar.. unfortunately not!!

Look at aragon's two posts........ both have been "pinked"

they are the right answers :)

1
Akand ·

this one...........................

11
Subash ·

this one....... what?? im not seeing anything

13
deepanshu001 agarwal ·

area for |y|=|sinx| is 4 and |y|= sinx is 2
sum1 plz verify.....

1
Pavithra Ramamoorthy ·

i thgt d same....... akand...............

62
Lokesh Verma ·

And the graph?

62
Lokesh Verma ·

And if it is that easy, I have added this part to this question

Plot the graph of

|y|=sin x

and

|y|= |sin x|

1
Pavithra Ramamoorthy ·

byah.. is ma area rit??????????

Your Answer

Close [X]