Solve for real values of x
\left( \int_{0}^{1}\frac{1}{t^{2}+2t\cos a+1}dt\right)x^2+\left(\int_{-3}^{3}\frac{t^{2}\sin 2t}{t^{2}+1}dt \right)x+2=0
Saw this on another forum... not very tough... only looks dirty...
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4 Answers
Lokesh Verma
·2009-09-24 04:26:18
one thing that you recognized correctly is coeff of x
can you say something better about the coeff of x^2?
Asish Mahapatra
·2009-09-24 20:22:42
coeff of x2 is positive and coeff of x=0 as that is odd func.
so no real value of x
coeff of x2 is positive
this is because
min value of t2+2tcosa+1 = (4.1.1-4cos2a)/4 = sin2a
which is ≥ 0