21-02-09 Fluid find shape

for every 1s revision and time pass[3]

1.the the shape of an ancient clock jug is such that water decends at constant rate at all times .....

if it falls by 4cm per hour ......

determine the shape of the jar(relation between y and x) ...

the radius of drainhole is 2mm and very small compaired to x !!!!!

23 Answers

24
eureka123 ·

Q1

33
Abhishek Priyam ·

isme.. answers pink kyun nahi hua... :(

24
eureka123 ·

yuup[1]................its truth[3][3]............main to chem ko jugaad kehta hoon.......har question mein naya concept lagta hai.....[9][9]khaskar inorganic mein..[9]

33
Abhishek Priyam ·

oh.. din saw yaha chem ki bejjati karni hai....

maine mauka kasie gawa diya... [2]

waise mera signature kafi hai uske liye.. ;)

24
eureka123 ·

he he he ....chem ki bezati har kahin hoti hai.............[3][3]

33
Abhishek Priyam ·

apply bernaullis theorem..

F/A=ρv2/2

or cheat it from here v=√2gh

1
Philip Calvert ·

ha or subject chem na hone ki wajah se answer dono se aa raha hai ..
[4][4]lol

1
°ღ•๓яυΠ·

vel of water kaise aaya?

33
Abhishek Priyam ·

Eureka... same chiz hai.. bas language and approach alag hai....[3]

33
Abhishek Priyam ·

Q.2

work done is always ∫F.dx

here F is constant..

so W=F.L

we have to find L

velocity of water is v=√2F/ρA .... A is area where force is apllied...

Volume V is emptied in time t so V=ts√2F/ρA
V=AL

AL=ts√2F/ρA

L=ts√2F/ρA3
Put A=V/L

L=ρV3/t2s22F

therefore W=FL=ρV3/2t2s2

24
eureka123 ·

oya hoye[3][3][3]............priyam bhai post kar chuke hain[3][3].............main bhi shaam se wait kar raha tha ki koi aur post kare .......maine ab post kiya aur priyam bhai ne bhi ab...........par hamare soln alag hain.........cheers[1]

24
eureka123 ·


3
iitimcomin ·

JUST TRYING TO CONTINUE INITIATIVE STARTED BY EUREKA!!!!

Q1.y = 0.4x4

soln. will be posted by tommorow ... in case no one attempts [2]

33
Abhishek Priyam ·

although i have left phy... but can't control myself.. [3]

33
Abhishek Priyam ·

Q.1

velocity with which water leaves.. =√2gy

dV/dt=rate of decrease of volume= a√2gy ....(i)
Volume decreased in time dt =Ï€x2.dy
dV/dt=Ï€x2dy/dt ...(ii)

dy/dt=k..(given =4cm/hr) ....(iii)

therefore from (i) (ii) (iii)

a√2gy=kÏ€x2

squaring and rearranging.. we get

y=(k2Ï€2) x4
2ga2

where k=4cm/hr
a=2mm

~~~ [1]

33
Abhishek Priyam ·

No one has solved till now... :O

33
Abhishek Priyam ·

:P

3
iitimcomin ·

thanxx yaar [3] ........ nish bhiyya put it up as QOD....he said u too deserved sum of ur questions to be put up but at that time this facility was nOT available!!!!!

33
Abhishek Priyam ·

[11]

QOD by IITcomin...

Congrats.. for this.. :)

1
chemistry organic ·

2nd wala toh kahin padhe the yaad nahi.....

3
iitimcomin ·

arre even here no ones trying [2][2][2][2][2][2]

62
Lokesh Verma ·

post on a seperate thread tomorrow :)

We will put it as another QOD if it si good... btw Priyam deserved atleast a few QOD's but then this feature was not there :)

3
iitimcomin ·

Q2.ASSUME IDEAL CONDITIONS AND FIND WORK DONE IN PUSHING ALL LIQUID OUT IN TIME t..................

ρV3/2S2t2

Your Answer

Close [X]