23-01-2009 Proof of LH Rule

f(x) is the numerator and g(x) is also the numerator... [7]

I think there is a mistake in question

but sir why would we apply LH rule then?????????????????because it wont be indeterminate then.....

Yes that should be a mistake...i think

then he wudn hav written 'also' ...

hmm...

if both are in num. then the limit should be 0 :) what was to prove...........?........?....?

If we take derivative of both num and den... we cancel 0 making factor.. if both have only one root at that pt... diff 1nce is enough if two repeated roots then f'(x) will have one root so f'(a) will be also 0 so we have to diff again ...

Ltx→af(x)/g(x) =Lt h→0 f(a+h)/g(a+h)

=Lth→0 f(a+h)-f(a)/g(a+h)-g(a) ((using g(a)=f(a)=0))

=Lth→0 (f(a+h)-f(a)/h)/(g(a+h)-g(a)/h)

=Lt x→a f'(x)/g'(x)

was this what u where expecting or r u expecting some thing other than this

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