11thoda lamba aa ra hai[2]
a+b+c=-2
ab+bc+ca=3
abc=-3
solve further!!!!!!!!!
I just got this method in the bag
but will be pleased to see more[1]
If a, b, c are the roots of x3+2x2+3x+3 then
\left( \frac{a}{a+1}\right)^3+\left( \frac{b}{b+1}\right)^3+\left( \frac{c}{c+1}\right)^3 is equal to
(Another good one i got from a student)
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10 Answers
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Now using the relations a3+b3+c3=(a+b+c)3-3(a+b)(b+c)(c+a), we can evaluate the entire expression....
If full solution is needed, do nudge me!
But I think this is sufficient, isn't it Nishant Sir?
11ya
by symmetry we observe that [12][12][12]
what do we observe[3]
