25th December 2008

A rectangular loop PQRS made from a uniform wire has length a, width b and mass m. It is free to rotate about the arm PQ, which remains hinged along a horizontal line taken as the y-axis. Take the vertically upward direction as the z-axis. A uniform magnetic field B=(3i+4k)B0 exists in the region. The loop is held in the x-y plane and a current I is passed through it. The loop is now released and is found to stay in the horizontal position.

What is the direction of current I in PQ?
Find the magnetic force on the arm RS?
Find the expression for I in terms of B0, a, b and m

JEE-2002

10 Answers

33
Abhishek Priyam ·

:) solving..

33
Abhishek Priyam ·

direction of current in PQ is in +ve y direction..

33
Abhishek Priyam ·

Force on RS

3B0bIk-4B0bIi

33
Abhishek Priyam ·

I=mg/6bB0

33
Abhishek Priyam ·

Hey manish bhaiya plz check!!

1357
Manish Shankar ·

Yeah priyam your answers are correct :)

33
Abhishek Priyam ·

Yippie!!

33
Abhishek Priyam ·

:-)

It was a subjective problem naa in IIT 2002

how many marks?

1357
Manish Shankar ·

Yeah it was subjective.

that time there were 12 questions in mains each of 5 marks

1
Akshay Pamnani ·

Got the answer
Good question,conceptual one

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