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a stone is dropped into a well 80m deep & impact of sound is heard after 4.25 s if g=10m/s2 d vel of sound in air is ...

let f(x) be a function such that f(x-1) +f(x+1)= 2 f(x) then find the period of f(x). ...

Q)At 0°c a body emits....... a) no radiation b)electromagnetic radiation of single wavelength c)electromagnetic radiation of all wavelengths that are emitted at room temperature d)electromagnetic radiation of fewer wavelengt ...

What is the value of limn→∞Πn=0n(1+1/22n)?? ...

limx→∞( (x+a)(x+b)(x+c) - x) = ?? ...

if 2<m<=4 and cosA = 1/2 ((m-2)(m+2)/m-1) .... 2b=ma prove that there are 2 values of thee third side which are in the ratio (m-1):1 ...

i wanted to apply to the Brilliant's correspondence program but am unsure of what exactly it looks like. Can anyone , who has taken the correspondence course, upload a few pages on the net from any chapter, like lets say elec ...

q a particle is projecte from horizontal plane to pass over two objects at height h n k n aslant distance d apart. wat s least possible speed of projection a)g(h+k+d) b)√[g(h+k+d)] c)h(g+k+d) d)√[h(g+k+d)] ...

two point charges are kept in space. they exert force on each other the magnitude and direction given by coulomb's law. now, if an infinitely large metallic plate of considerable thickness is placed between the charges, do th ...

Show that the sum of the (m+n)th and (m-n)th terms of an A.P is equal to twice the mth term. ...

Can Charles law be stated with initial volume at 100 degree C? give reason! If no why?If yes , with what modification(s)? ...

a stone is dropped into a well 80m deep & impact of sound is heard after 4.25 s if g=10m/s2 d vel of sound in air is ...

a stone is dropped into a well 80m deep & impact of sound is heard after 4.25 s if g=10m/s2 d vel of sound in air is ...

Q a particle moves on acurved path with constant sped v .the acceleration of particle at x=0 is 2av2 .the path of particle is a)straight line b)parabolic c)eliptical d)none ...

What is the minimum force needed to move a block on the ground? Hint: Answer is not μmg! ...

A thin nonconducting ring of radius R has a linear charge density λ = λ0 cos φ, where λ0 is a constant, φ is the azimuthal angle. Find the magnitude of the electric field strength on the axis of the ring as a function of ...

Let f:(4,6)--> (6,infinity) be a funtion defined by f(x) = x +[x/2], where [] is GIF.Then f-1(x) = a. x-[x/2] b.-x-2 c.x-2 d. NOT How to find the inverse of such funtions involving GIF, fractional part etc.. And soln and e ...

εIf P(n) = 2+ 4 + 6+....+ 2n, n N, then P(k) = k(k+1) + 2 => P(k+1) = (k+1)(k + 2) + 2 for all k belongs to N. So we can conclude that P(n) = n(n+1)+2 for a. all n belonging to N b.n>1 c.n>2 d. nothing can be said A ...

The relation "congruence modulo m" on the set I of all integers is a.An equivalence b.A partial order relation c. reflexive and symmetric d.reflexive and anti symmetric Pls explain the Q and option B ...

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If funtion :R-->R be such that f(x)= x - [x], where [] is GIF..Then f-1(x)= a. 1/x-[x] b.[x]-x c.not defined d.NOT ...

If the quadratic eqn ax2+bx+c=0 has -2 as one of its roots then ax + by +c =0 represents a. A family of concurrent lines b.A family of parallel lines c.A single line d. A lineperpendicular to x-axis I thought to be B But the ...

The value of 2*a and 2*b such that (where a and b satisfies) Ltx-->0 x(1+acosx)-b sinx =1 ------------------------- x3 a. 5,3 b. 5,-3 c.-5,-3 d.NOT ...

The value of limx-->0(cosx + a sinbx)1/x Ans was e^ab The method was using the expansion...but pls explain how the higher powers gets cancelled out..(because denominator of cos and sin goes as 2! , 3! respectively) ...

The value of Ltn->infinity(1/1.3 +1/3.5+....n terms) a. 1/4 b.1/2 c. 1 d. NOT ...

observe the given sequence of nos. , which has two missing nos. at the end. 20 18 17 16 14 14 11 12 ? ? a) 8,10 b)12,11 c)13,9 d) 9,10 ans nahin pata ...

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this is really a simple one...... just wanted to check my answer. So pls co-operate [1] Using transformations or otherwise , find correct four places of decimals the value \prod_{1}^{5}{} (zi+1)/(2zi-1) where Zi are the roots ...

a simple one 4 bitsat *Image* ...

the no. of bonds in CaC2 is ..... ...